In ΔABC, m∠ACB = 90°, and m∠ACD = 45°.
Find CD, if BC = 3in.

Answer:
Step-by-step explanation:
We need to find CD
since ANGLE ACD=45
ANGLE BCD=45
COS 45=CD/CB
1/2=CD/3
so CD =3/2
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Answer:
3/√2 inches
Step-by-step explanation:
From the ∆ACB,
∠ACD + ∠DCB = 90°
45° + ∠DCB = 90°
∠DCB = 90° - 45°
∠DCB = 45°
Using sine rule on ∆CDB to get BC,
BC/∠CDB = CD/∠CBD
BC/sin90° = CD/sin45°
3/sin90° = CD/sin45°
3 = CD/(1/√2)
3 = √2 × CD
CD = 3/√2 inches