[tex]\dfrac{2x+3}{15}=\dfrac{9}{10}\qquad\text{cross multiply}\\\\10(2x+3)=(9)(15)\qquad\text{use distributive property}\\\\(10)(2x)+(10)(3)=135\\\\20x+30=135\qquad\text{subtract 30 from both sides}\\\\20x=105\qquad\text{divide both sides by 20}\\\\x=\dfrac{105}{20}\\\\x=5\dfrac{5}{20}\\\\x=5\dfrac{1}{4}\to x=5.25\\\\Answer:\ \boxed{x=5\dfrac{1}{4}=5.25}[/tex]
