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Write an expression to represent the sum of the numbers in the nth row of Pascal’s triangle.
a.
n/2
c.
2n
b.
n²
d.
2n


Please select the best answer from the choices provided

A
B
C
D

Respuesta :

frika

Answer:

Choose from your options option where is given [tex]2^n[/tex]

Step-by-step explanation:

Pascal's triangle is a number triangle with numbers arranged in staggered rows such that each n-th row consists of n+1 binomial coefficients.

The sum of the numbers in the n-th row of Pascal’s triangle is

[tex]C^n_0+C^n_1+C^n_2+C^n_3+\dots +C^n_{n-2}+C^n_{n-1}+C^n_n.[/tex]

This sum for every n is always equal to [tex]2^n.[/tex]

Answer: The answer is 2^n, which could be c or d, depending on which lost the ^ in transcription.


Step-by-step explanation:

Row 1 is 0 1 1 0, sum 2^1

Row 2 is 0 0+1 1+1 1+0 0 sum 2^2

Row 3 is 0 0+1 1+2 2+1 1+0 0 sum 2^3

Notice that every number on row n is used as a term twice in row n+1. So the sum doubles.


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