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Write the balanced chemical reaction for the formation of Fe2(SO4)3 from Fe2O3 and SO3 and determine how many moles of Fe2(SO4)3 are formed when 12.7 Mol of SO3 are reacted.

Respuesta :

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Answer:

4.23 mol

Step-by-step explanation:

Step 1. Balanced equation

Fe₂O₃ + 3SO₃ ⟶ Fe₂(SO₄)₃

Step 2. Calculation:

You want to convert moles of SO₃ to moles of Fe₂(SO₄)₃.

The molar ratio is 1 mol Fe₂(SO₄)₃:3 mol SO₃

Moles of Fe₂(SO₄)₃ = 12.7 mol SO₃ × (1 mol Fe₂(SO₄)₃/3 mol SO₃)

Moles of Fe₂(SO₄)₃ = 4.23 mol Fe₂(SO₄)₃

The reaction will form 4.23 mol of Fe₂(SO₄)₃.

The balanced chemical equation for the formation of Fe₂(SO₄)₃ from Fe₂O₃ and SO₃ is Fe₂O₃ + 3SO₃ → Fe₂(SO₄)₃ and 4.233 mol of Fe₂(SO₄)₃ are formed when 12.7 mol of SO₃ are reacted.

What is Stoichiometry ?

Stoichiometry helps us use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.

What is Balanced Chemical equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The balanced chemical reaction for the formation of Fe₂(SO₄)₃ from Fe₂O₃ and SO₃ is

Fe₂O₃ + 3SO₃ → Fe₂(SO₄)₃

According to Stoichiometry moles of Fe₂(SO₄)₃ is

= 12.7 mol of SO₃ × [tex]\frac{1\ mol\ Fe_2 (SO_4)_3}{3\ mol\ SO_3}[/tex]

= 4.233 mol of Fe₂(SO₄)₃

Thus from the above conclusion we can say that the balanced chemical equation for the formation of Fe₂(SO₄)₃ from Fe₂O₃ and SO₃ is Fe₂O₃ + 3SO₃ → Fe₂(SO₄)₃ and 4.233 mol of Fe₂(SO₄)₃ are formed when 12.7 mol of SO₃ are reacted.

Learn more about the Stoichiometry here: brainly.com/question/14935523

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