Hello!
The answer is:
[tex]x1=0.53\\x2=-0.17[/tex]
Why?
The quadratic formula is:
[tex]x=\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}[/tex]
We have that:
[tex]a=11\\b=-4\\c=-1[/tex]
By substituting we have:
[tex]x=\frac{4+-\sqrt{-4^{2}-4*11*-1 } }{2*11}=\frac{4+-\sqrt{16+44} }{22}=\frac{4+-\sqrt{60} }{22}=\frac{4+-(7.75)}{22}[/tex]
[tex]x1=\frac{4+7.75}{22}=0.53\\\\x2=\frac{4-7.75}{22} =-0.17[/tex]
Have a nice day!
