Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• csc x = [tex]\frac{1}{sinx}[/tex] and sec x = [tex]\frac{1}{cosx}[/tex]
• sin2x = 2sinx cosx
Consider the left side
2 csc 2x = 2 × [tex]\frac{1}{sin2x}[/tex]
= 2 × [tex]\frac{1}{2sinxcosx}[/tex] ( cancelling the 2's )
= [tex]\frac{1}{sinx}[/tex] × [tex]\frac{1}{cosx}[/tex]
= cscx secx = right side ⇒ verified
