400N:
[tex]F = G\frac{Mm}{r^{2} }[/tex]
So lets make the first Force F1 and the second force after the reduction F2:
[tex]F_{1} = G\frac{Mm}{r^{2} } \\[/tex]
One third each mass so:
[tex]F_{2} = G \frac{\frac{1}{3}M \frac{1}{3} m }{r^{2} }[/tex]
Pull out the constant:
[tex]F_{2} = \frac{1}{9} (G\frac{Mm}{r^{2} } )[/tex]
Now we can recognize that F1 equals all the stuff we have in parentheses so we can replace it!
[tex]F_{2} = \frac{1}{9} F_{1}[/tex]
Now plug in our value for F1 which is 3600N
[tex]F_{2} = \frac{1}{9} (3600)[/tex]
So:
F2 = 400N
Answer:
the answer is 400n
Explanation:
I just took the quiz I hope you pass
