I need this immediately!! Put the equation in standard form with a positive X coefficient. Y + 6 = 3/2 ( x - 4 ) HELP!!

Answer:
see explanation
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
given
y + 6 = [tex]\frac{3}{2}[/tex](x - 4)
Multiply through by 2 to eliminate the fraction
2y + 12 = 3(x - 4) ← distribute
2y + 12 = 3x - 12 ( subtract 2y from both sides )
12 = 3x - 2y - 12 ( add 12 to both sides )
24 = 3x - 2y, that is
3x - 2y = 24 ← in standard form
Answer:
3/2x -y = 12
Step-by-step explanation:
Y + 6 = 3/2 ( x - 4 )
Distribute the 3/2
y+6 = 3/2x - 12/2
y+6 = 3/2x -6
Subtract 6 from each side
y+6-6 = 3/2x -6-6
y = 3/2x -12
Subtract 3/2x from each side
-3/2x +y = 3/2x-3/2x -12
-3/2x +y = -12
We want a positive x so multiply by -1
-1(-3/2x +y) = -1* -12
3/2x -y = 12