what is the equation of a circle with center (2 -3) and radius 3

Choice A
x^2+y^2=r^2 is the mother function of a circle centered at the origin with radius r.
then x^2+y^2=9 is the equation of a circle with radius 3 centered at the origin
to translate the graph 2 unites to the right, add the opposite of 2 which is -2 to the x value inside the function, and to translate the graph 3 units down, then add the opposite which is 3 to the y value inside the function.
which makes the equation became (x-2)^2+(y+3)^2=9 and that is choice A
The equation of a circle with a center (2 -3) and radius of 3 will be given as (x - 2)² + (y + 3)² = 9. Then the correct option is A.
A circle can be characterized by its center's location and its radius's length.
Let the center of the considered circle be at the (h,k) coordinate.
Let the radius of the circle be 'r' units.
Then, the equation of that circle would be:
(x - h)² + (y - k)² = r²
The equation of a circle with a center (2 -3) and radius of 3 will be
We have
(h, k) = (2, -3)
r = 3
Then we get
(x - 2)² + (y + 3)² = 3²
(x - 2)² + (y + 3)² = 9
Then the correct option is A.
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