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Amphitrite1040

Hey there!

[tex]\bold{x^2+2x-24=0}[/tex]

  • Firstly, you have to work out (factor out) the left side of your equation
  • [tex]\bold{Like:(x-4)(x+6)=0}[/tex]
  • Since, we are working factoring, let's set your numbers to [tex]\bold{0}[/tex]
  • [tex]\bold{Like:x-4=0}[/tex]  [tex]\bold{or}[/tex] [tex]\bold{x+6=0}[/tex]
  • [tex]\uparrow[/tex]After solving the equation we just created, we should have the value(s) of the [tex]\bold{x-values}[/tex] [tex]\downarrow[/tex]
  • [tex]\boxed{\boxed{\bold{Answer:x=4[or]x=-6}}}[/tex]

Good luck on your assignment and enjoy your day!

~[tex]\bold{LoveYourselfFirst:)}[/tex]

wegnerkolmp2741o

Answer:

x = 4   x=-6

Step-by-step explanation:

x^{2} + 2x - 24 = 0

Move the constant to the right

x^2 +2x -24+24 = 24

x^2 +2x = 24

b =2

We take b/2 and then square it

2/2 =1 1^1 =1

Add 1 to both sides

x^2 +2x+1 = 24+1

The left side is (x+b/2)^2

(x+1)^2 = 25

Take the square root of each side

sqrt((x+1)^2 ) = ±sqrt(25)

x+1 = ±5

Subtract 1 from each side

x+1-1 = -1±5

x = -1±5

x = -1+5  and x= -1-5

x = 4   x=-6

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