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A sample of a gas has a pressure of 248mm Hg when the volume is 1.05L. What is the pressure of the gas when the volume is 3.98L?

Respuesta :

So Boyle's Law equation is going to be used to solve this problem.

Boyle's Law: (P1)(V1)=(P2)(V2)

So, based on the question. Let's first note down what is given.

P1= 248mm Hg

V1= 1.05L

P2= ? (<-- What we are going to be solving for)

V2= 3.98L

Based on what we know, we can just simply plug it into the equation.

So...

1. (248 mmHg) (1.05L) = (P2) (3.98L)

2. (248 mm Hg) (1.05L)

   -----------------------------    =     P2

        (3.98L)

3. P2 = 65.4 mm Hg is your answer

samueladesida43

The pressure of a gas that has a pressure of 248mmHg when the volume is 1.05L is 65.43mmHg.

BOYLE'S LAW:

  • The pressure of a gas can be calculated given its volume using Boyle's law equation as follows:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (mmHg)
  2. P2 = final pressure (mmHg)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

  • According to this question, a sample of a gas has a pressure of 248mm Hg when the volume is 1.05L. The pressure when the volume is 3.98L is calculated as follows:

  • 248 × 1.05 = P1 × 3.98

  • 260.4 = 3.98P1

  • P1 = 260.4 ÷ 3.98

  • P1 = 65.43mmHg

  • Therefore, the pressure of a gas that has a pressure of 248mm Hg when the volume is 1.05L is 65.43mmHg.

Learn more about Boyle's law at: https://brainly.com/question/1437490?referrer=searchResults

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