Respuesta :

First, solve the first part.
(3x-4)²=
=9x²-24x+16

...

Second, 9x²-24x+16-4x-3x²=
=6x²-28x+16

...

Therefore, the answer is #3

Answer:

(1) [tex]-12x^{2} +28x-16[/tex]

Step-by-step explanation:

[tex](3x-4)^{2} =3x(3x-4)-4(3x-4)\\=9x^{2} -12x-12x+16\\=9x^{2} -24x+16\\4x -3x^{2} -(9x^{2} -24x+16)\\\\4x-3x^{2} -9x^{2} +24x-16\\\\ -3x^{2} -9x^{2} +4x+24x-16\\-12x^{2} +28x-16[/tex]