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A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s.
. The ball's height h (in feet) after t seconds is given by the following.
h= 160 - 12t - 16t^2

How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.

Respuesta :

changeabledead

Answer:

Step-by-step explanation:

Solve the quadratic equations for h = 0

Quadratic formula:

(12 +- sqrt(144-4(-16)(160)))/32

(12 +- sqrt(10384))/32

t= -2.81 (disregard this because a negative doesn't make since in this context)

t=3.56

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