Respuesta :

carlosego

Answer: [tex]3x^{2}+6x-12=0[/tex]

Step-by-step explanation:

By definition a quadratic equation in general quadratic form is:

[tex]ax^{2}+bx+c=0[/tex]

Therefore, to write the equation given in the problem above in in general quadratic form, you only need to subtract 12 from both sides of the equation.

Keeping this on mind, you obtain:

[tex]3x^{2}+6x-12=12-12\\3x^{2}+6x-12=0[/tex]

zainebamir540

Answer:

3x²+6x-12 = 0

Step-by-step explanation:

We have given a quadratic equation.

3x²+ 6x = 12

We have to rewrite above equation in general quadratic equation.

The general form of quadratic equation is:

ax²+bx+c = 0 where a,b and c are constant.

Adding -12 to both sides of given equation, we have

3x²+6x+(-12) = 12+(-12)

3x²+6x-12 = 12-12

3x²+6x-12 = 0 is general form of quadratic equation where a = 3,b = 6 and c = -12.