The table below shows two equations:

Equation 1 |4x βˆ’ 3| βˆ’ 5 = 4
Equation 2 |2x + 3| + 8 = 3


Which statement is true about the solution to the two equations?
Equation 1 and equation 2 have no solutions.
Equation 1 has no solution, and equation 2 has solutions x = βˆ’4, 1.
The solutions to equation 1 are x = 3, βˆ’1.5, and equation 2 has no solution.
The solutions to equation 1 are x = 3, βˆ’1.5, and equation 2 has solutions x = βˆ’4, 1.

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The solutions to equation 1 are x = 3, βˆ’1.5, and equation 2 has no solution.

What is the conclusion about equation 1 ?

The given equation is, |4x βˆ’ 3| βˆ’ 5 = 4

We have to solve the equation by options given below in the question.

We put the given values to examine whether the equation satisfy or not,

For, x = 3,

|4(3)-3| -5

= |12-3|-5

= 9-5 (taking positive sign for positive root)

= 4

So, this is a solution.

Again, for x = -1.5,

|4(-1.5)-3| -5

= |-6-3|-5

= -(-9)-5 (taking negative sign for negative root)

= 9-5

= 4

So, this is also a solution.

Therefore, the solutions to equation 1 are x = 3, βˆ’1.5

What is the conclusion about equation 2 ?

The given equation is, |2x + 3| + 8 = 3

We have to solve the equation by options given below in the question.

We put the given values to examine whether the equation satisfy or not,

For x = -4,

|2(-4)+ 3| + 8

= |-8+3| + 8

= -(-5)+8 Β  (taking negative sign for negative root)

= 13 β‰  3

So, this is not a solution.

Again, for x = 1

|2(1)+ 3| + 8

= |2+3|+8

= 5+8 Β  Β  (taking positive sign for positive root)

= 13 β‰  3

So, this is not a solution.

Therefore, equation 2 has no solution.

Learn more about solution of equation here :

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