Respuesta :

Answer:

a)

[tex]\dfrac{23}{16}[/tex]

b)

[tex]\dfrac{104}{9}[/tex]

c)

[tex]\dfrac{275}{9}[/tex]

d)

[tex]\dfrac{140}{13}[/tex]

e)

[tex]\dfrac{103}{5}[/tex]

f)

[tex]\dfrac{259}{2}[/tex]

Step-by-step explanation:

" A fraction in which the numerator is greater than the denominator "

We have to change each of the mixed fraction into improper fraction:

We know that the mixed fraction is converted into fraction as:

[tex]a\frac{b}{c}=\dfrac{a\times c+b}{c}[/tex]

a)

[tex]1\frac{7}{16}[/tex] could be written as:

[tex]=\dfrac{1\times 16+7}{16}\\\\=\dfrac{16+7}{16}\\\\=\dfrac{23}{16}[/tex]

b)

[tex]11\frac{5}{9}[/tex]

[tex]=\dfrac{11\times 9+5}{9}\\\\=\dfrac{99+5}{9}\\\\=\dfrac{104}{9}[/tex]

c)

[tex]30\frac{5}{9}[/tex]

[tex]\dfrac{30\times 9+5}{9}\\\\=\dfrac{270+5}{9}\\\\=\dfrac{275}{9}[/tex]

d)

[tex]10\frac{10}{13}[/tex]

[tex]\dfrac{10\times 13+10}{13}\\\\=\dfrac{130+10}{13}\\\\=\dfrac{140}{13}[/tex]

e)

[tex]24\frac{3}{5}\\\\=\dfrac{24\times 5+3}{5}\\\\=\dfrac{100+3}{5}\\\\\dfrac{103}{5}[/tex]

f)

[tex]129\frac{1}{2}\\\\\\=\dfrac{19\times 2+1}{2}\\\\=\dfrac{258+1}{2}\\\\=\dfrac{259}{2}[/tex]

aachen

Answer:

We need to convert the following fractions into improper fraction.

a. [tex]1 \frac{7}{16}[/tex], b. [tex]11 \frac{5}{9}[/tex], c. [tex]30 \frac{5}{9}[/tex]

d. [tex]10 \frac{10}{13}[/tex], e. [tex]24 \frac{3}{5}[/tex], and f. [tex]129 \frac{1}{2}[/tex]

We know that an improper fraction is a fraction in which the numerator is greater than the denominator.

Now, to convert a mixed fraction, say [tex]a\frac{b}{c}[/tex] into improper fraction as, [tex]a\frac{b}{c}=\frac{a\times c+b}{b}[/tex]

Now, let us consider each part one by one.

a. [tex]1 \frac{7}{16}[/tex]

[tex]1\frac{7}{16}=\frac{16\times1+7}{16} =\frac{23}{16}[/tex]

b. [tex]11 \frac{5}{9}[/tex]

[tex]11\frac{5}{9}=\frac{11\times9+5}{9} =\frac{104}{9}[/tex]

c. [tex]30 \frac{5}{9}[/tex]

[tex]30\frac{5}{9}=\frac{30\times9+5}{9} =\frac{275}{9}[/tex]

d. [tex]10 \frac{10}{13}[/tex]

[tex]10\frac{10}{13}=\frac{10\times13+10}{13} =\frac{140}{13}[/tex]

e. [tex]24 \frac{3}{5}[/tex]

[tex]24\frac{3}{5}=\frac{24\times5+3}{5} =\frac{123}{5}[/tex]

f. [tex]129 \frac{1}{2}[/tex]

[tex]129\frac{1}{2}=\frac{129\times2+1}{2} =\frac{259}{2}[/tex]