Answer:
The solution of the system of equations are
x=1,y=-1,z=1
Step-by-step explanation:
we have
4x+3y+5z=6 ----> solve for z
5z=6-4x-3y
z=(6-4x-3y)/5 ----> equation A
6x+8y+6z=4 ----> equation B
4x+2y+6z=8 ----> equation C
Substitute equation A in equation B and equation C
6x+8y+6((6-4x-3y)/5)=4
Multiply by 5 both sides
30x+40y+36-24x-18y=20
6x+22y=-16 ----> equation D
4x+2y+6((6-4x-3y)/5)=8
Multiply by 5 both sides
20x+10y+36-24x-18y=40
-4x-8y=4 ----> equation E
Solve the system of equations D and E by graphing
The intersection point both graphs is the point (1,-1)
see the attached figure
so
x=1. y=-1
Find the value of z
z=(6-4(1)-3(-1))/5
z=1
therefore
The solution of the system of equations are
x=1,y=-1,z=1
