Answer:
The length of bank side ,s = [tex]\sqrt{3}[/tex] unit.
The length of hypotenuse, h= 2 unit.
Step-by-step explanation:
Given in 30-69-90 triangle
We know that
[tex]tan\theta= \frac {perpendicular}{base}[/tex]
[tex]sin\theta=\frac { perpendicular}{ hypotenuse}[/tex]
When[tex]\theta=30^{\circ}[/tex]
[tex]sin\theta= \frac{1}{h}[/tex]
[tex]sin30^{\circ}=\frac {1}{h}[/tex]
[tex]sin30^{\circ}=\frac{1}{2}[/tex]
Therefore,[tex]\frac{1}{h} =\frac{1}{2}[/tex]
By cross multiply we get
h=2
[tex]tan30^{\circ}=\frac{1}{s}[/tex]
[tex]tan30^{\circ}=\frac {1}{\sqrt{3}}[/tex]
[tex]\frac{1}{s} =\frac{1}{\sqrt{3}}[/tex]
By cross multiply we get
s=[tex]\sqrt{3}[/tex]
Hence, the length of side of bank, s=[tex]\sqrt{3}[/tex] unit
Length of hypotenuse ,h=2 unit.
