Answer:
[tex]y=\frac{-7}{5}x+\frac{48}{5}[/tex] is equation of BC
Step-by-step explanation:
Given that AB and BC form a right angled triangle at point B.
i.e. BC is perpendicular to AB
Line AB contains two points (-3,-1) and (4,4)
Slope of AB =[tex]\frac{y2-y1}{x2-x1} =\frac{4+1}{4+3} =\frac{5}{7}[/tex]
Slope of BC would be -1/slope of AB since AB and BC are perpendicular
Slope of BC =\frac{-7}{5}
Also we got a point on BC as B.
Use point slope formula
[tex]y-y1=m(x-x1)\\y-4=\frac{-7}{5}(x-4)\\y=\frac{-7}{5}x+\frac{48}{5}[/tex][tex]y-y1=m(x-x1)\\y-4=\frac{-7}{5}(x-4)\\y=\frac{-7}{5}x+\frac{48}{5}[/tex]
Answer:
-7x − 5y = -48
Step-by-step explanation:
This was correct on plato :D
