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Radio signals travel at a rate of 3 × 10^8 meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 4,2 × 10*7 meters?

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aasiyahi

Answer:

0.14 seconds

Step-by-step explanation:

[tex]\frac{4.2*10^{7} m}{3*10^{8} \frac{m}{8} } =1.4*10^{-1}s=0.14s[/tex]

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