Help!! Picture below
1.ABC is a right isosceles triangle, and M is the midpoint of AC.

What are the coordinates of point C?
Answer options
A.(a/2, 0)
B.(a, 0)
C.(a, a)
D.(0, a/2)

2.ABC is a right isosceles triangle, and point M is the midpoint of AC. What are the coordinates of point M?
Answer options
A.(a/2, 0)
B.(a, 0)
C.(a, a)
D.(0, a/2)

Help Picture below1ABC is a right isosceles triangle and M is the midpoint of ACWhat are the coordinates of point CAnswer options Aa2 0Ba 0Ca a D0 a2 2ABC is a class=

Respuesta :

Answer:

Option A. [tex](a/2,0)[/tex]

Step-by-step explanation:

we know that

If triangle ABC is a right isosceles triangle

then

AB=AC

m<ABC=m<ACB=45°

therefore

The coordinate of point C is [tex](a,0)[/tex]

the x-coordinate of the midpoint M is equal to

[tex](0+a)/2=a/2[/tex]

The coordinates of point M are [tex](a/2,0)[/tex]

The coordinate of C is (a,0) and the coordinate of M is (a/2,0)

The triangle is said to be a right isosceles triangle.

This means that the coordinates of C are: the y coordinate of B, and the x coordinate of A.

So, we have:

C = (a,0)

The midpoint M is then calculated as:

[tex]M = \frac{A + C}2[/tex]

This gives

[tex]M = \frac{(0,0) + (a,0)}2[/tex]

Add the corresponding coordinates

[tex]M = \frac{(0 + a,0 + 0)}2[/tex]

[tex]M = \frac{(a,0)}2[/tex]

Divide

[tex]M = (\frac a2,0)[/tex]

Hence, the coordinate of C is (a,0) and the coordinate of M is (a/2,0)

Read more about right isosceles triangle at:

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