Answer:
9.52x10²⁰ sodium ions
Explanation:
First, we need to convert the mass in moles (n)
n = mass/molar mass
The moalr mass is given in g/mol, so let's transform the mass in gram:
1 g ------------ 1000 mg
x g------------- 99.6 mg
By a direct simple three rule:
1000x = 99.6
x = 0.0996 g
n = 0.0996/126.05
n = 7.90x10⁻⁴ mol of Na₂SO₃
The ionization reaction is:
Na₂SO₃ → 2Na⁺ + SO₃⁻
So, for 1 mol of Na₂SO₃, will be two moles of Na⁺ (sodium ion), then:
1 mol of Na₂SO₃ --------------- 2 moles of Na⁺
7.90x10⁻⁴ ------------------------- x
By a simple direct three rule:
x = 1.58x10⁻³ mol of Na⁺
Avogadro has related the number of moles with the number of the matter: atoms, ions, molecules. So, 1 mol has 6.02x10²³ ions.
1 mol ------------------- 6.02x10²³
1.58x10⁻³ mol ----------- x
By a direct simple three rule:
x = 9.52x10²⁰ sodium ions
There are 9.52 × 10²⁰ sodium ions in 99.6 mg of Na₂SO₃.
First, we will convert 99.6 mg to g using the conversion factor 1 g = 1000 mg.
[tex]99.6 mg \times \frac{1g}{1000mg} = 0.0996 g[/tex]
Next, we want to convert 0.0996 g to moles of Na₂SO₃. The required conversion factor is its molar mass (126.05 g/mol).
[tex]0.0996 \times \frac{1mol}{126.05 g} = 7.90 \times 10^{-4} mol[/tex]
Then, to convert 7.90 × 10⁻⁴ moles to molecules, we will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.
[tex]7.90 \times 10^{-4} mol \times \frac{6.02 \times 10^{23} molecule }{1 mol} = 4.76 \times 10^{20} molecule[/tex]
According to the chemical formula, there are 2 Na⁺ ions per molecule of Na₂SO₃. The number of sodium ions in 4.76 × 10²⁰ molecules of Na₂SO₃ is:
[tex]4.76 \times 10^{20} molecule \times \frac{2Na^{+}ion }{1 molecule} = 9.52 \times 10^{20} Na^{+}ion[/tex]
There are 9.52 × 10²⁰ sodium ions in 99.6 mg of Na₂SO₃.
You can learn more about Avogadro's number here: https://brainly.com/question/13302703
