Answer:
60 child tickets and 72 adult tickets
Step-by-step explanation:
Let x denote the number of child tickets sold and y the number of adult tickets sold. The problem involves solving the following system of linear equations; x+y=132 and 5.2x+8.6y=931.2. Using technology to solve this simultaneous equation yields; x= 60, y =72
For this case, we propose a system of two equations with two unknowns.
Let:
x: Represents the number of children's tickets
y: Represents the number of adult tickets
[tex]5.20x + 8.60y = 931.20\\x + y = 132[/tex]
So, we clear x from the second equation:
x = 132-y
We replace in the first one.
[tex]5.20 (132-y) + 8.60y = 931.20\\686.4-5.20y + 8.60y = 931.20\\-5.20y + 8.60y = 931.20-686.4\\3.4y = 244.8\\y = \frac {244.8} {3.4}\\y = 72[/tex]
72 adult tickets were sold.
[tex]x = 132-y\\x = 132-72\\x = 60[/tex]
60 tickets for children were sold
Answer:
60 tickets for children
72 adult tickets
