PART A)
Energy of the light is given as
[tex]E = \frac{hc}{\lambda}[/tex]
now we have
[tex]\lambda = 8.45 \times 10^{-7}m[/tex]
now we have
[tex]E = \frac{6.6 \times 10^{-34} (3 \times 10^8)}{8.45 \times 10^{-7}}[/tex]
now we have
[tex]E = 2.34 \times 10^{-19} J[/tex]
PART B)
When light of different wavelength interact with a given surface then surface has property to absorb the light of definite energy due to which that light is completely absorbed while other all energy is reflected back by the surface
Here same occur in the given example as here energy of green light is completely reflected by the surface while energy of red light is completely absorbed by the surface
PART C)
Wavelength = wavelength of gamma rays are less than the wavelength of visible light
Energy = energy of gamma rays are more than the energy of visible light
Frequency = frequency of gamma rays is more than the frequency of visible light
speed = speed of all electromagnetic waves are same so speed will be same for both
