destinygom07
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Examine this system of equations. What integer should the second equation be multiplied by so that when the two equations are added together, the x term is eliminated? PLEASE HELP ME
3/4x+1/7y=6
1/8x-3/5y=16

Respuesta :

we should multiply the 1/8 on the 2nd equation, by some number "n", such that our result will be equals to -3/4, namely the above x-coefficient but negative, or different sign, so

[tex]\bf \begin{cases} \cfrac{3}{4}x+\cfrac{1}{7}y&=6\\[2em] \cfrac{1}{8}x-\cfrac{3}{5}y&=16 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1}{8}n=-\cfrac{3}{4}\implies \cfrac{n}{8}=-\cfrac{3}{4}\implies 4n=-24\implies n=\cfrac{-24}{4}\implies n=-6 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1}{8}x(-6)\implies \cfrac{-6}{8}x\implies -\cfrac{3}{4}x[/tex]

shubhamchouhanvrVT

Multiply the second equation with -6 to eliminate the x term.

What is an equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Two equations are given below:-

3/4x+1/7y=6

1/8x-3/5y=16

The 1/8 on the 2nd equation, by some number "n", such that our result will be equal to -3/4, namely the above x-coefficient but negative, or different sign,

( 1 / 8 )n = ( -3/8)

n = ( 8 x -3)/4

n = 2 x -3

n =-6

Hence, multiply the second equation with -6

To know more about equations follow

https://brainly.com/question/2972832

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