Answer : The mass of the substance is, 28 g
Solution :
Formula used :
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
where,
Q = heat absorbs = 1932 J
m = mass of the substance = ?
c = specific heat of substance = [tex]4.29J/g^oC[/tex] Â Â Â
[tex]\Delta T=\text{Change in temperature}[/tex] Â
[tex]T_{final}[/tex] = final temperature = [tex]42^oC[/tex]
[tex]T_{initial}[/tex] = initial temperature = [tex]26^oC[/tex]
Now put all the given values in the above formula, we get the mass of the substance.
[tex]1932J=m\times 4.29J/g^oC\times (42-26)^oC[/tex]
[tex]m=28.146g=28g[/tex]
Therefore, the mass of the substance is, 28 g
