*15 points

A squirrel jumps straight up with an initial vertical velocity of 16 feet per second. How many times does the squirrel reach a height of 4 feet? Explain your answer.

Respuesta :

4 because 4 times 4 is 16

Jumping refers to launching itself upwards. The squirrel reach a height of 4 feet once per jump.

What does something reaching to a height means?

Suppose that you've made a pole stand vertical on the ground. It is a measurement tool. Then, if some object goes through a particular level on that measuring pole's line' (parallel to ground), we say that it reached to that height.

Now, refer to the figure attached below.

Using the third equation of motion, we get:

  • Initial velocity = u = 16 feet per second(straight up)
  • Final velocity = 0 (squirrel slowed down to 0 velocity in air, its the maximum height h reached by squirrel).
  • Acceleration = -Gravitational acceleration = -g = -32 feet /sec² approx.

(acceleration taken negative as it is downwards, and due to sign convention used, we take upward as +ve, downwards as -ve, left as -ve, right as +ve (sign of quantity if quantity(vector) is in these directions)).

[tex]v^2 = u^2 + 2as\\0 = 16^2 -2gh\\\\h \approx \dfrac{256}{2 \times 32} \approx 4\: \rm feet[/tex]

Thus, we see that the squirrel will reach at max 4 feet, and then falls to ground after reaching that. it doesn't cross 4 feet more than once per jump, but touches 4 feet height(theoretically, ideally) once only.

Thus,  The squirrel reach a height of 4 feet once per jump.

Learn more about equation of motion here:

https://brainly.com/question/5955789

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