Will mark brainliest if right...


Given two functions

j(x)=−4x+2


k(x)=5+4x


What is the function rule for (kj)(x)?

A. (kj)(x)=−16x2−12x+10

B. (kj)(x)=16x2+12x−10

C. (kj)(x)=16x2−12x−10

D. (kj)(x)=−16x2+12x+10

Respuesta :

Answer:

(kj)(x)= -16x^2- 12x +10

Step-by-step explanation:

Ver imagen cmdezarn

Answer:

Option A is correct

[tex](kj)(x)=-16x^2-12x+10[/tex]

Step-by-step explanation:

Given the functions are as follows:

[tex]j(x) = -4x+2[/tex]

[tex]k(x) = 5+4x[/tex]

We have to find (kj)(x).

Consider,

[tex](kj)(x) = k(x)j(x)[/tex]

Substitute the given values we have;

[tex](kj)(x) = (5+4x)(-4x+2)[/tex]

Using distributive property, [tex]a \cdot (b+c) = a\cdot b+ a\cdot c[/tex]

[tex](kj)(x)=-20x+10-16x^2+8x[/tex]

Combine like terms;

[tex](kj)(x)=-12x+10-16x^2[/tex]

or

[tex](kj)(x)=-16x^2-12x+10[/tex]

Therefore, the function rule for  (kj)(x) is, [tex]-16x^2-12x+10[/tex]