Answer:
1. x
2. 3x-6
Step-by-step explanation:
1) y=|x−3|+|x+2|−|x−5| , IF -2 < X < 3
|x−3| will be less than zero if -2 < X < 3 so rewrite it as 3-x
|x+2| will be greater than zero if -2 < X < 3 so we can leave it as x+2
|x−5| will be less than zero if -2 < X < 3 so we rewrite it as 5-x
1. 3-x + x+2 - (5-x)
Combine like terms
5 - (5-x)
Distribute
5 - 5+x
x
1) y=|x−3|+|x+2|−|x−5| , IF 3 < X < 5
|x−3| will be greater than zero if 3 < X < 5 so leave it as x-3
|x+2| will be greater than zero if 3 < X < 5 so we can leave it as x+2
|x−5| will be less than zero if -2 < X < 3 so we rewrite it as 5-x
x-3 + x+2 - (5-x)
Combine like terms
2x-1 - (5-x)
Distribute
2x-1 - 5+x
3x-6
