HELP BRAINIEST AND LOTS OF POINTS Two twins, Mason and Jason, play a game in which they have a pile of 99 marbles. They can take anywhere from 1 to 10 marbles each turn. Whoever takes the last marble loses. Mason starts. Both play optimally. Who wins, and how many turns will Mason and Jason take combined? NEED NOW

Mason's optimal strategy is to keep the total number of marbles at 11n+1, so he will take 10 marbles to start. For each move Jason makes, Mason will take a number of marbles that makes the sum from the two turns be 11.

After each of Mason's 9 turns, the number of remaining marbles will be ...

89, 78, 67, 56, 45, 34, 23, 12, 1

It doesn't matter how many marbles Jason takes. He will lose on his 9th turn.

ahmedislife ahmedislife · Answer 2 · 2019-03-23T20:02:22+01:00

Mason's best strategy is to stay the overall variety of marbles at 11n+1, thus he can take ten marbles to begin. for every move Jason makes, Mason can take variety of marbles that creates the add from the 2 turns be eleven.

After every of Mason's nine turns, the amount of remaining marbles are

89, 78, 67, 56, 45, 34, 23, 12, 1

It doesn't matter what number marbles Jason takes. He can lose on his ninth flip.

mason will win after 18 moves