Suppose f(x) = x^2+2. Find the graph of f(2/3x)

Because the function is in the formula x^2 + 2, it will be symmetrical across the y axis.
This only leaves graphs 1 and 4.
I can't see the y values for your graphs; however, below are you plotting points - (X,Y)
(-5,18.66...), (-4,12.66...), (-3,8), (-2,4.66...), (-1,2.66...), (0,2), (1,2.66..), (2,4.66...), (3,8), (4,12.66...), (5,18.66...)
Answer:
The answer is graph 4.
Step-by-step explanation:
I literally just guessed it and got it right lol. Stay safe, ya’ll.