The 2 Triangles are similar.
What is the ratio of the corresponding side lengths? Thanks!

Answer:
see explanation
Step-by-step explanation:
The ratios of corresponding sides are
[tex]\frac{AB}{A'B'}[/tex] = [tex]\frac{BC}{B'C'}[/tex] = [tex]\frac{AC}{A'C'}[/tex], that is
[tex]\frac{4}{2}[/tex] = [tex]\frac{9}{4.5}[/tex] = 2