Answer:
[tex]x=5+\frac{29}{z}-\frac{y}{z}[/tex]
[tex]y=5z+29-xz[/tex]
Step-by-step explanation:
Given: [tex](4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24[/tex]; find x and y.
Let's start with finding x first. Let's distribute the left side of the equation.
[tex]-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24[/tex]
Let's move everything we can to the left side of the equation. Some things will cancel out.
[tex]5z^2+29z=xz^2+yz[/tex]
Now, let's move the term that includes [tex]x[/tex] to the left side of the equation. Everything else should be moved to the right.
[tex]-xz^2=-5z^2-29z+yz[/tex]
Let's get rid of the negative sign in front of [tex]x[/tex] by dividing both sides by -1.
[tex]xz^2=5z^2+29z-yz[/tex]
To get [tex]x[/tex] completely isolated, divide both sides by [tex]z^2[/tex].
[tex]\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}[/tex]
Simplify.
[tex]x=5+\frac{29}{z}-\frac{y}{z}[/tex]
Let's solve for y. We will start with the distributed and simplified equation to make it easier.
[tex]5z^2+29z=xz^2+yz[/tex]
Now, let's move the term that includes [tex]y[/tex] to the left side of the equation. Everything else should be moved to the right.
[tex]-yz=-5z^2-29z+xz^2[/tex]
Again, let's get rid of the negative sign in front of the [tex]y[/tex] by dividing both sides by -1.
[tex]yz=5z^2+29z-xz^2[/tex]
To isolate y, divide both sides by z.
[tex]\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}[/tex]
Simplify.
[tex]y=5z+29-xz[/tex]
