Can someone help me answer this calculus I problem?

Answer:
[tex]f^{-1}(x) = \sqrt [7]{y - 3}[/tex]
Step-by-step explanation:
ƒ.(x) = x⁷ + 3
Rename f.(x) as y
y = x⁷ + 3
Solve for x :
x⁷ = y - 3
Take the seventh root of each side
[tex]x = \sqrt [7]{y - 3}[/tex]
Switch x and y
[tex]y = \sqrt [7]{x - 3}[/tex]
Rename y as the inverse function
[tex]f^{-1}(x) = \sqrt [7]{y - 3}[/tex]