Answer:
Step-by-step explanation:
Okay so solve this this is how you do it
[tex]-2x-y=-4[/tex] and [tex]x+2y=5[/tex]
To cancel out the X we have to make x into 2 x
[tex]1(-2x-y=-4)\\2(x+2y=5)\\\\[/tex]
[tex]-2x-y=-4\\2x+4y=10[/tex]
we can cancel out -2x and 2x now leaving us with
[tex]-y=-4\\4y=10[/tex]
add them both and solve for y
[tex]3y=6\\y=\frac{6}{3}\\y=2[/tex]
Now just substitute 2 for y
[tex]-2x-2=-4\\-2x=-4+2\\-2x=-2\\x=\frac{-2}{-2} \\x= 1[/tex]
Or
[tex]x+2(2)=5\\x+4=5\\x=5-4\\x=1[/tex]
In both the equations your answer will be the same
Hope this helps :)
If you have an doubt or need further help just reply :)
