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An electron with a charge value of 1.6x10^-19 C is in the presence of an electric field of 300 N/C when located between a pair of oscilloscope deflecting plates. What force does the electron experience?

Respuesta :

AL2006

(1.6 x 10⁻¹⁹ C) x (300 N/C) = 4.8 x 10⁻¹⁷ Newton

The force experienced by the electron is 4.8×10⁻¹⁷ N.

Electric Field: An electric field is a region or space, where an electric force can be experienced or felt.

The formula of electric force is

F = E×Q............... Equation 1

Where F = Electric force, E = Electric field, Q = Charge.

From the question,

Given: Q = 1.6×10⁻¹⁹ C, E = 300 N/C

Substitute these values into equation 1

F = (1.6×10⁻¹⁹)(300)

F =  4.8×10⁻¹⁷ N.

Hence, The force experienced by the electron is 4.8×10⁻¹⁷ N.

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