Answer:
option C. [tex]V=1,980\ yd^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the triangular pyramid is equal to
[tex]V=\frac{1}{3}Bh[/tex]
where
B is the area of the triangular base
h is the height of the pyramid
In this problem we have
[tex]B=330\ yd^{2}[/tex]
[tex]h=18\ yd[/tex]
substitute in the formula
[tex]V=\frac{1}{3}(330)(18)=1,980\ yd^{3}[/tex]
