in the figure PQ is parallel to RS. the length of RP is 6 cm; the length of PT is 18 cm; the length of QT is 21 cm; what is the length of SQ?

Answer:
Option A. [tex]SQ=7\ cm[/tex]
Step-by-step explanation:
we know that
In the figure
The triangles PTQ and RTS are similar by AA Similarity Theorem
so
Remember that
If two figure are similar, then the ratio of its corresponding sides is equal
so
[tex]\frac{PT}{RT}=\frac{QT}{ST}[/tex]
we have
[tex]PT=18\ cm[/tex]
[tex]RT=RP+PT=6+18=24\ cm[/tex]
[tex]QT=21\ cm[/tex]
[tex]SQ=ST-21\ cm[/tex] ------> equation A
substitute the values and solve for ST
[tex]\frac{18}{24}=\frac{21}{ST}[/tex]
[tex]ST=21*24/18[/tex]
[tex]ST=28\ cm[/tex]
substitute the value of ST in the equation A to find the value of SQ
[tex]SQ=28-21=7\ cm[/tex]