Respuesta :
[tex]n\cdot1\cdot\dfrac12\cdot\dfrac13\cdot\dfrac14\cdot\dfrac15=\dfrac n{5!}[/tex]
[tex]\dfrac12\cdot\dfrac14\cdot\dfrac16\cdot\dfrac18\cdot\dfrac1{10}=\dfrac{3\cdot5\cdot7\cdot9}{10!}[/tex]
So we have
[tex]\dfrac n{5!}=\dfrac{3\cdot5\cdot7\cdot9}{10!}[/tex]
[tex]n=\dfrac{3\cdot5\cdot7\cdot9}{6\cdot7\cdot8\cdot9\cdot10}[/tex]
[tex]n=\dfrac{3\cdot5}{6\cdot8\cdot10}[/tex]
[tex]n=\dfrac1{2\cdot8\cdot2}[/tex]
[tex]n=\dfrac1{32}[/tex]