Respuesta :

lucic

Answer:

D (3,1)

Step-by-step explanation:

solving simultaneous equations

Arrange equations

2x+y=7

3x-4y=5

make y side cancell by addition by multiplying by 4 and 1 as shown

4{2x+y=7}

1{3x-4y=5}

8x+4y=28

3x-4y=5

11x=33

x=33/11=3

substitute for x=3 in 3x-4y=5

9-4y=5

4=4y

y=1

Answer:

D(3,1)

Step-by-step explanation:

The given equations are:

[tex]2x+y=7...(1)[/tex]

and

[tex]3x-4y=5...(2)[/tex]

Multiply equation (1) by 4.

[tex]\Rightarrow 8x+4y=28...(3)[/tex]

Add equation (2) and (3)

[tex]\Rightarrow 11x=33[/tex]

Divide through by 11.

[tex]\Rightarrow x=3[/tex]

Put x=3 into equation (1)

[tex]2(3)+y=7[/tex]

[tex]6+y=7[/tex]

[tex]y=7-6[/tex]

[tex]y=1[/tex]

The solution is (3,1)

The correct choice is D