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An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s/s to reach a speed of 50.0 m/s as it left the bow. During this ACCELERATION, what was the net force on the arrow to the nearest newton? *
1 point
A. 3 N
B. 833 N
C. 300 N
D. None of the above

Respuesta :

Answer;

C. 300 N

Explanation;

From Newton second's Law of motion, the resultant force is directly proportional to the rate of change in momentum.

Therefore;

F = ma ; where F is the resultant force, m is the mass and a is the acceleration.

Therefore;

F = 0.06 kg × 5,000 m/s/s

  = 300 N

Lanuel

The net force on the arrow to the nearest newton during this acceleration is: C. 300 Newton.

Given the following data:

  • Mass of arrow = 0.06 kg
  • Acceleration of arrow = 5,000 [tex]m/s^2[/tex]
  • Speed = 50.0 m/s

To determine the net force on the arrow to the nearest newton during this acceleration, we would apply Newton's Second Law of Motion:

Newton's Second Law of Motion states that the acceleration of an object or body is directly proportional to the net force acting on the object or body while being inversely proportional to its mass.

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]Net\;force = mass \times acceleration[/tex]

Substituting the given parameters into the formula, we have;

[tex]Net\;force = 0.06 \times 5000[/tex]

Net force = 300 Newton

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