Respuesta :
V1/T1 = V2/T2, so
V2 = V1 * T2 / T1
V2 = 54.2 L * 345 K / 115 K
V2 = 163 L
V2 = V1 * T2 / T1
V2 = 54.2 L * 345 K / 115 K
V2 = 163 L
The gas will occupy 162.6L of volume.
What is Ideal Gas Law ?
According to Ideal Gas Law , for unit mole of an ideal gas , product of Pressure and Volume is equal to product of Universal Gas Constant and Temperature,
This can be written as
PV = nRT
When Pressure is kept constant , According to Charles law , Volume is directly proportional to the temperature , and increase in temperature will increase the volume and vice versa.
[tex]\rm \dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}[/tex]
It is given in the question
A 54.2 L sample of gas at 115 K is heated to 345 K, at constant pressure.
Volume of Gas = 54.2 L
Temperature = 115 K
Pressure = ?
Temperature new = 345K
Putting the values in the equation
54.2/115 = Volume new / 345
new Volume = 345 * 54.2 / 115
Volume new = 162.6 L
The gas will occupy 162.6L of volume.
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