make it equal to zero
minus 6 from both sides
x^2+6x+3=0
quadratic formula
x=[tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex]
x=[tex] \frac{-6+/- \sqrt{6^{2}-4(1)(3)} }{2(1)} [/tex]
x=[tex] \frac{-6+/- \sqrt{36-12} }{2} [/tex]
x=[tex] \frac{-6+/- \sqrt{24} }{2} [/tex]
x=[tex] \frac{-6+/- 2\sqrt{6} }{2} [/tex]
x=[tex] -3+/- \sqrt{6} [/tex]
E and F are answer
