There are 50 different ways she can select her 3 sweets.
The solution is obtained through a combination where we choose "r of n", where r is the amount of things we choose and n the total number of things that can be chosen.
A box contains sweets of 6 different flavours.
There are atleast 2 sweets of each flavour.
A girl selects 3 sweets from the box. Given that these 3 sweets are not all of the same flavour, calculate the number of different ways she can select her 3 sweets.
The three chosen sweets are not all of the same flavour, either she has chosen 3 different flavours, or she has chosen 2 different flavours.
If 3 different, then she is choosing 3 from 6, and we have 6C3 = 20.
If there are two different flavours, then there is one of one flavour and two of a different flavour.
The one has 6 choices of flavours and once chosen the two have five choices, making 6x5=30 possibilities.
Hence 50 ways in total.
Hence, there are 50 different ways she can select her 3 sweets.
Learn more about permutation combination here;
brainly.com/question/3929817
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