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The probability that mary will win a game is 0.05, so the probability that she will not win is 0.95. if mary wins, she will be given $80; if she loses, she must pay $4. if x = amount of money mary wins (or loses), what is the expected value of x? (round your answer to the nearest cent.)

Respuesta :

calculista

Answer:

[tex]x=\$0.20[/tex]

Step-by-step explanation:

we know that

The expected value is the sum of: [(each of the possible outcomes) × (the probability of the outcome occurring)]

In this problem we have

[tex]x=0.05(\$80)-095(\$4)=\$0.20[/tex]

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