A point is chosen at random in the circle. What percent of the time will the point be in the square? Round to the nearest tenth of a percent.

A point is chosen at random in the circle What percent of the time will the point be in the square Round to the nearest tenth of a percent class=

Respuesta :

Answer:

[tex]63.7\%[/tex]

Step-by-step explanation:

we know that

To find the percent divide the area of the square by the area of the circle

step 1

Find the area of the circle

The area of the circle is

[tex]A=\pi r^{2}[/tex]

we have

[tex]r=1\ in[/tex]

substitute the values

[tex]A=(3.14)(1)^{2}=3.14\ in^{2}[/tex]

step 2

Find the area of the square

The area of the square is

[tex]A=b^{2}[/tex]

where

b is the length side of the square

we have

[tex]D=2\ in[/tex] ---> the diagonal of the square is equal to the diameter of the circle

Applying Pythagoras Theorem

[tex]D^{2}=b^{2}+b^{2}[/tex]

substitute the values

[tex]2^{2}=2b^{2}[/tex]

[tex]4=2b^{2}[/tex]

[tex]b^{2}=2\ in^{2}[/tex] ------> the area of the square

step 3

Find the percent

[tex]\frac{2}{3.14}= 0.6369[/tex]

Convert to percent

[tex]0.6369*100=63.69\%[/tex]

Round to the nearest tenth of a percent

[tex]63.7\%[/tex]