[tex] \frac{shorter leg}{hypotenuse}[/tex] = sin(30) = cos(60)
Luckily 30° and 60° are nice angles and [tex]sin(30) = cos(60) = \frac{1}{2} [/tex]
[tex] \frac{shorter leg}{hypotenuse} = \frac{1}{2} [/tex]
We can rearrange the equation to give
[tex]hypotenuse = 2(shorter leg)[/tex]
[tex]hypotenuse = 2(10)[/tex]
Hypotenuse = B, 20 inches
