Answer:
1±√2
Step-by-step explanation:
To solve the quadratic, use the quadratic formula. Substitute a = -1, b = 2 and c = 1.
The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex].
Substitute and you'll have:
[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{2^2-4(-1)(1)} }{2(-1)}=\frac{-2+/-\sqrt{4+4} }{-2)}[/tex]
[tex]\frac{-2+/-\sqrt{8} }{-2}=\frac{-2+/-2\sqrt{2} }{-2} = 1 +/- \sqrt{2}[/tex]
