Given: circle k(O), mAM=125°, mEF=31°, m∠MAF=75° Find: m∠AME


PLS help SQDANCEFAN - FIRST ANSWER GETS BRAINLIEST and 12pts!

Given circle kO mAM125 mEF31 mMAF75 Find mAME PLS help SQDANCEFAN FIRST ANSWER GETS BRAINLIEST and 12pts class=

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Answer:

The measure of angle A.M.E is [tex]58\°[/tex]

Step-by-step explanation:

step 1

Find the measure of arc M.E

we know that

The inscribed angle is half that of the arc it comprises.

[tex]m<M.A.F=\frac{1}{2}(arc\ M.E+arc\ E.F)[/tex]

we have

[tex]m<M.A.F=75\°[/tex]

[tex]arc\ E.F=31\°[/tex]

substitute the values

[tex]75\°=\frac{1}{2}(arc\ M.E+31\°)[/tex]

[tex]150\°=(arc\ M.E+31\°)[/tex]

[tex]arc\ M.E=150\°-31\°=119\°[/tex]

step 2

Find the measure of arc A.F

we know that

[tex]arc\ M.E+arc\ E.F+arc\ A.F+arc\ A.M=360\°[/tex] -----> by complete circle

substitute the values

[tex]119\°+31\°+arc\ A.F+125\°=360\°[/tex]

[tex]119\°+31\°+arc\ A.F+125\°=360\°-275\°=85\°[/tex]

step 3

Find the measure of angle A.M.E

we know that

The inscribed angle is half that of the arc it comprises.

[tex]m<A.M.E=\frac{1}{2}(arc\ A.F+arc\ E.F)[/tex]

substitute the values

[tex]m<A.M.E=\frac{1}{2}(85\°+31\°)=58\°[/tex]