Answer:
B. [tex]x=\frac{-5\pm\sqrt{13}}{6}[/tex]
Step-by-step explanation:
We have been given an equation [tex]3x^2+5x+1=0[/tex]. We are asked to solve for x.
We will use quadratic formula to solve our given problem as our given equation is in form [tex]ax^2+bx+c=0[/tex].
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Substitute given values:
[tex]x=\frac{-5\pm\sqrt{5^2-4(3)(1)}}{2(3)}[/tex]
[tex]x=\frac{-5\pm\sqrt{25-12}}{6}[/tex]
[tex]x=\frac{-5\pm\sqrt{13}}{6}[/tex]
Therefore, the solutions for our given equation are [tex]x=\frac{-5\pm\sqrt{13}}{6}[/tex] and option B is the correct choice.
